Re: php on the Command line

Chris Adams wrote: > > > i understand how argv and argc work, but if someone leaves off a > > required field, or something such as a password , is it possible to stop > > and prompt them ? i know no perl or c, and im fairly efficent in php, so > > i'd like to stick with this. > > You could just do something as simple as: > if ($argc != 3) { > die("usage: scriptname username password database"); > } else { > list($Username, $Password, $Database) = $argv; > } im using something similar to that, it accepts -n -i etc, etc $c = $argc; while(list($key, $pair) = each($argv) ){ if($pair == "-i"){ $n = 1 + $key; $ip = $argv["$n"]; $n = 0; } if($pair == "-u"){ $n = 1 + $key; $user = $argv["$n"]; $n = 0; } ...... } # required fields.. if(!$ip || !$domain || !$user || !$passwd){ echo "you forgot something\n"; echo "usage is:$argv[0] -i [ip] -d [domain] -u [user] -p [password] [OPTIONS]\n"; .. then say things... exit; } Works quite well too. going to switch it to switch() case: statements later on, just testing and debuging the script first.. If anyone else has an idea on how to make that even cleaner, id like to hear it. :) > If you want the user to be able to enter a value, try using fgets on stdin (See the fopen() > docs for > instructions on how to open stdin, stdout, or stderr). It should be somewhat like this: > > $stdout = fopen("php://stdout"); > $stdin = fopen("php://stdin"); > > fputs($stdout, "Username: "); > fgets($stdin, $Username); > I really really need to sit down sometime and read EVERY page of that manual :) thanks bjorn > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net