Re: Xpath arguments in variable

If you needed the double-quotes in the Xpath expression when the constant is used , then you probably need them in the variable version. $v = $row->xpath('//membernumber[. = "'.$MemberId.'"]'); That should put the double-quotes in for you... On 15/09/10 09:33, Sridhar Pandurangiah wrote:

-------- Original Message -------- Subject: Re: Xpath arguments in variable From: php-general@garydjones.name (Gary) To: Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST) Whats wrong with $v = $row->xpath('//membernumber[. = ' . $MemberId . ']'); ? Am I not understanding what you are trying to ask? -------------------- I tried this but doesn't work. I guess the above statement is concatenating the entire string and the substitution isn't happening What I am trying to do is as follows $MemberId = 'A192'; $v = $row->xpath('//membernumber[. = ' . $MemberId . ']'); The $MemberId should be substituted with A192 and then the xpath query should be executed. The result should be that I locate the membernumber XML element that has the value A912. Best regards Sridhar

Sridhar Pandurangiah wrote:

now I need to pass this value to XPath within a string variable say $v = $row->xpath('//membernumber[. = $MemberId]'); But this doesnt work due to the quotes. What I intend PHP to do is to substitute the value for $MemberId and then execute the XPath query. I have grappled with it for a few days before posting this.

Whats wrong with $v = $row->xpath('//membernumber[. = ' . $MemberId . ']'); ? Am I not understanding what you are trying to ask?

-- Peter Ford, Developer phone: 01580 893333 fax: 01580 893399 Justcroft International Ltd. www.justcroft.com Justcroft House, High Street, Staplehurst, Kent TN12 0AH United Kingdom Registered in England and Wales: 2297906 Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17 1XS