Re: Re: Xpath arguments in variable

Managed to resolve it. Phew! $v = $row->xpath('//membernumber[. = ' . '"' . $MemberId . '"' . ']'); works. Best regards Sridhar -------- Original Message -------- Subject: Re: [PHP] Re: Xpath arguments in variable From: ash@ashleysheridan.co.uk (Ashley Sheridan) To: Date: Wed Sep 15 2010 14:04:33 GMT+0530 (IST)

On Wed, 2010-09-15 at 14:03 +0530, Sridhar Pandurangiah wrote:

-------- Original Message -------- Subject: Re: Xpath arguments in variable From: php-general@garydjones.name (Gary) To: Date: Wed Sep 15 2010 13:34:11 GMT+0530 (IST) Whats wrong with $v = $row->xpath('//membernumber[. = ' . $MemberId . ']'); ? Am I not understanding what you are trying to ask? -------------------- I tried this but doesn't work. I guess the above statement is concatenating the entire string and the substitution isn't happening What I am trying to do is as follows $MemberId = 'A192'; $v = $row->xpath('//membernumber[. = ' . $MemberId . ']'); The $MemberId should be substituted with A192 and then the xpath query should be executed. The result should be that I locate the membernumber XML element that has the value A912. Best regards Sridhar

Sridhar Pandurangiah wrote:

now I need to pass this value to XPath within a string variable say $v = $row->xpath('//membernumber[. = $MemberId]'); But this doesnt work due to the quotes. What I intend PHP to do is to substitute the value for $MemberId and then execute the XPath query. I have grappled with it for a few days before posting this.

Whats wrong with $v = $row->xpath('//membernumber[. = ' . $MemberId . ']'); ? Am I not understanding what you are trying to ask?

Did you try using double quotes? Thanks, Ash http://www.ashleysheridan.co.uk