Re: Issue with Quick Email validation

On 10 March 2011 11:07, <robert@myself.com> wrote: > Thank you, that did get me past that part! > > Had also to put in else statement to call Email function, without doing so the mail was sent > even though giving error > > Robert > > > > > > > > -----Original Message----- > From: Louis Huppenbauer <louis.huppenbauer@gmail.com> > To: robert@myself.com > Cc: php-general@lists.php.net > Sent: Thu, Mar 10, 2011 11:38 am > Subject: Re: [PHP] Issue with Quick Email validation > > > try != instead of ==, that should do the trick. > > > > 2011/3/10  <robert@myself.com>: > >> Hi, > >> I'm newbie to PHP and this list, possible not a new question so forgive me if > > it's a repeat > >> I have a form where I want the submitter Email ID to only be from one domain > >> > >> Here's the part I'm having issues with > >> > >>                                        $domain = explode( >> "@", $who); > >>                        if ( $domain[1] == "company.com") { > >>                                        echo $domain[1]; > >>                                        echo("<h3>Email >> invalid.</h3>"); > >>                                        exit; > >>                                        } > >> > >> First Echo is just for me to check > >> I type in a correct Email ID, say me@company.com > >> > >> The return of this is: > >> > >> company.com > >> Email invalid. >> As far as I can see this if statement should not fall in, what am I missing? Why bother asking for the entire address? Just ask for the name part and display the domain name on the form? <label for="email">Enter your email address: <input type="text" name="email" id="email" />@company.com</label> sort of thing. -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY