RE: [PHP] Issue with Quick Email validation
| From: | Ford, Mike | Date: | Thu, 10 Mar 2011 11:40:47 +0000 |
| Subject: | RE: [PHP] Issue with Quick Email validation | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-311763@lists.php.net to get a copy of this message | ||
Apart form the obvious error already solved, in this situation I would not be forcing my users to
type in an element that only has one option -- I would display the form box with the text
"@company.com" immediately after it, and only expect the unique part to be entered.
Cheers!
Mike
--
Mike Ford,
Electronic Information Developer, Libraries and Learning Innovation,
Leeds Metropolitan University, C507 City Campus,
Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom
Email: m.ford@leedsmet.ac.uk
Tel: +44 113 812 4730
> -----Original Message-----
> From: robert@myself.com [mailto:robert@myself.com]
> Sent: 10 March 2011 09:45
> To: php-general@lists.php.net
> Subject: [PHP] Issue with Quick Email validation
>
> Hi,
> I'm newbie to PHP and this list, possible not a new question so
> forgive me if it's a repeat
> I have a form where I want the submitter Email ID to only be from
> one domain
>
> Here's the part I'm having issues with
>
> $domain = explode( "@",
> $who);
> if ( $domain[1] == "company.com") {
> echo $domain[1];
> echo("<h3>Email
> invalid.</h3>");
> exit;
> }
>
> First Echo is just for me to check
> I type in a correct Email ID, say me@company.com
>
> The return of this is:
>
> company.com
> Email invalid.
>
>
> As far as I can see this if statement should not fall in, what am I
> missing?
>
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