Re: Function mktime() documentation question
| From: | Tedd Sperling | Date: | Thu, 08 Mar 2012 23:12:36 +0000 |
| Subject: | Re: Function mktime() documentation question | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-316939@lists.php.net to get a copy of this message | ||
On Mar 7, 2012, at 4:28 PM, Daniel Brown wrote:
> On Wed, Mar 7, 2012 at 15:03, Tedd Sperling <tedd.sperling@gmail.com> wrote:
>> Hi gang:
>>
>> I am using the getdate(mktime()) functions to get month data (i.e., name of month, first
>> weekday, last day, number of days).
>>
>> To get the number of days for a specific month, I use:
>>
>> // $current_month is the month under question
>>
>> $next_month = $current_month + 1;
>> $what_date = getdate(mktime(0, 0, 0, $next_month, 0, $year));
>> $days_in_current_month = $what_date['mday'];
>>
>> That works for me!
>>
>> However, if you read the documentation, namely:
>>
>> http://php.net/manual/en/function.mktime.php
>>
>> It states:
>>
>> --- quote
>>
>> day
>>
>> The number of the day relative to the end of the previous month. Values 1 to 28, 29, 30 or
>> 31 (depending upon the month) reference the normal days in the relevant month. Values less than 1
>> (including negative values) reference the days in the previous month, so 0 is the last day of the
>> previous month, -1 is the day before that, etc. Values greater than the number of days in the
>> relevant month reference the appropriate day in the following month(s).
>> --- un-quote
>>
>> From my code, the number of days in a month can be found by using 0 as the first index of
>> the next month -- not the last day of the previous month.
>
> I fail to follow. Your code is looking ahead to next month
> (April), then using the 0 day, which means it's getting the last day
> (31) of the current month (March). There's no such thing as a 0
> April, hence anything less than one should count backward.
>
> --
> </Daniel P. Brown>
Daniel:
Yes, it uses next month to figure out this month -- that's my point.
See my reply to Mike Ford.
Cheers,
tedd
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