Re: Function mktime() documentation question

On Fri, Mar 9, 2012 at 9:23 AM, Tedd Sperling <tedd.sperling@gmail.com> wrote: > On Mar 8, 2012, at 6:53 PM, Daniel Brown wrote: > On Mar 8, 2012 6:14 PM, "Tedd Sperling" <tedd.sperling@gmail.com> wrote: >> >> > Side-point: I find it interesting that getdate() has all sorts of neat descriptions >> > for the current month (such as, what weekday a numbered day is), but lacks how many days are in the >> > month. Doesn't that seem odd? >> >> Oh, I see what you're saying now.  Well, using getdate(), how else would you think to >> pass the parameter to get the last day other than using the current month and the last day (which >> would then obviously be overkill, of course). > > Well.. you could use any number that exceeds 31 -- or -- as I would have suggested if it had > been up to me, zero day would provide the number of days in *that* month rather than the number of > days in the previous month, which was the point of my post. > >> All of this aside, though, you may instead want to use something along the lines of >> date('d',strtotime('last day of this month')); in tandem with your date >> formatting. > > That's a good idea, but > >> date('d',strtotime('last day of this month')); > > > gives me the number of days in *this* month, but not the next, or previous, month. > > I need the result to be whatever date was selected -- something like: > > $number_days = date('d',strtotime('last day of April, 2014')); > > But that doesn't work. > > You see, I need something that makes sense to students. The idea that you have to use the zero > day (whatever that is) of the next month to see how many days there are in this month is strange and > confusing -- again my point.. > > Thus far, the following looks better than what I came up with:: > > $what_date = getdate(mktime(0, 0, 0, $mon, 32, $year)); > $days_in_month = 32 - $what_date['mday']; > > But it's still strange. > > I was using: > >        // get the last day of the month >        $cont = true; >        $tday = 27; >        while (($tday <= 32) && ($cont)) >                { >                $tdate = getdate(mktime(0,0,0,$mon,$tday,$year)); >                if ($tdate["mon"] != $mon) >                        { >                        $lastday = $tday - 1; >                        $cont = false; >                        } >                $tday++; >                } > > It made sense, but was too long. I figured there should be something better and easier to > explain -- but I'm still looking. function count_days($month, $year) { return (mktime(0, 0, 0, $month+1, 1, $year) - mktime(0, 0, 0, $month, 1, $year))/86400; }