Re: PHP and C
| From: | German Geek | Date: | Sat, 18 Jul 2015 09:40:09 +0000 |
| Subject: | Re: PHP and C | ||
| References: | 1 2 3 4 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-325002@lists.php.net to get a copy of this message | ||
What do you actually want to achieve?
On Sat, 18 Jul 2015 at 21:39 German Geek <geek.de@gmail.com> wrote:
> Of course you need to give the variable $someNumber a value.
>
> On Sat, 18 Jul 2015 at 03:45 Ethan Rosenberg <
> erosenberg@hygeiabiomedical.com> wrote:
>
>> Thanks -
>>
>> On 07/17/2015 12:34 AM, German Geek wrote:
>> > You cannot run a C program and grab input from PHP interactively! You
>> would have to pipe the input
>> > in as so:
>> >
>> > // untested!
>> > $number =
echo $someNumber | /var/www/TestScanf;
>> > echo 'number in php<br />';
>> >
>> > Also, returning the number num in C's main function is wrong. You
>> should return 0 if successful and
>> > another int if the program has an error.
>> >
>> >
>> >
>> <snip>
>>
>> You cannot run a C program and grab input from PHP interactively! You
>> would have to pipe the input
>> in as so:
>>
>> // untested!
>> $number = echo $someNumber | /var/www/TestScanf;
>> echo 'number in php<br />';
>>
>> Also, returning the number num in C's main function is wrong. You should
>> return 0 if successful and
>> another int if the program has an error.
>>
>>
>> CODE
>>
>>
>> $number = echo $someNumber | /var/www/TestScanf;
>> //$number = /var/www/TestScanf;
>> echo 'number in php<br />';
>>
>> echo $number;
>>
>> OUTPUT
>>
>>
>> Notice: Undefined variable: someNumber in /var/www/Scanf.php on line 36
>> number in php
>> Enter your Number 0
>>
>> TIA
>>
>> Ethan
>>
>