Re: preg_replace() in 4.0.4
| From: | Monte Ohrt | Date: | Mon, 08 Jan 2001 00:22:08 +0000 |
| Subject: | Re: preg_replace() in 4.0.4 | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-33146@lists.php.net to get a copy of this message | ||
escape the $ signs in the replace array first, so $1 becomes \$1, etc.
Daniel Baldoni wrote:
> G'day folks,
>
> With the upgrade to 4.0.4, preg_replace() now does substitutions for $n in
> the replacement strings (I say strings, because it's the easiest way of doing
> mass substitutions over an array). This has caused me severe grief (as there
> doesn't appear to be any way to stop it).
>
> I have an application which reads in a PostScript template file and replaces
> occurrences of '@' delimited strings with specific values (basically, a
> "variable subsituter"). Some of the replacement strings may contain dollar
> amounts and so a '$' may (or may not) be present. If a '$' is present in a
> string, it will be followed by a digit. When I call preg_replace() in this
> application, all 3 arguments are arrays.
>
> What I'm looking for is some alternative method to do what I'm doing without
> writing a custom array_walk()er. If str_replace() or ereg_replace() could
> work on arrays as preg_replace() does, that'd be fine. Alternatively, if
> there was some way to tell preg_replace() to *NOT* do the substitution,
> that would work (for me) to.
>
> Any suggestions? Thanks in advance.
>
> --
> -------------------------------------------------------+---------------------
> Daniel Baldoni BAppSc, PGradDipCompSci | Technical Director
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