preg_replace() in 4.0.4

From: Date: Sun, 07 Jan 2001 15:53:08 +0000
Subject: preg_replace() in 4.0.4
Groups: php.general 
Request: Send a blank email to php-general+get-33096@lists.php.net to get a copy of this message
G'day folks, With the upgrade to 4.0.4, preg_replace() now does substitutions for $n in the replacement strings (I say strings, because it's the easiest way of doing mass substitutions over an array). This has caused me severe grief (as there doesn't appear to be any way to stop it). I have an application which reads in a PostScript template file and replaces occurrences of '@' delimited strings with specific values (basically, a "variable subsituter"). Some of the replacement strings may contain dollar amounts and so a '$' may (or may not) be present. If a '$' is present in a string, it will be followed by a digit. When I call preg_replace() in this application, all 3 arguments are arrays. What I'm looking for is some alternative method to do what I'm doing without writing a custom array_walk()er. If str_replace() or ereg_replace() could work on arrays as preg_replace() does, that'd be fine. Alternatively, if there was some way to tell preg_replace() to *NOT* do the substitution, that would work (for me) to. Any suggestions? Thanks in advance. -- -------------------------------------------------------+--------------------- Daniel Baldoni BAppSc, PGradDipCompSci | Technical Director require 'std/disclaimer.pl' | LcdS Pty. Ltd. -------------------------------------------------------+ 856B Canning Hwy Phone/FAX: +61-8-9364-8171 | Applecross Mobile: 041-888-9794 | WA 6153 URL: http://www.lcds.com.au/ | Australia -------------------------------------------------------+--------------------- "Any time there's something so ridiculous that no rational systems programmer would even consider trying it, they send for me."; paraphrased from "King Of The Murgos" by David Eddings. (I'm not good, just crazy)

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