Re: Function -> Sending URL's

No, that wont work - unfortunately the purpose of the function is to read the values from a database then add them to the URL. So the URL is sent to the function - but the values within the URL will come from the database which is accessed from within the function. Thanks, Abe ----- Original Message ----- From: "DanO" <dano@informano.net> To: "Abe" <abe@fish.tm>; <php-general@lists.php.net> Sent: Thursday, January 11, 2001 9:34 PM Subject: RE: [PHP] Function -> Sending URL's > > you are assigning the variable within the function, then calling the > function with the variable. > > this is a variable scoping issue. > > try this: > > <? > function testPassVar($url) { > echo "<a href=\"$url\">Click</a>"; > } > > $company = "TEST"; > $url = 'asdfasdf.php3?name='.$company; > testPassVar($url); > ?> > > > > -----Original Message----- > From: Abe [mailto:abe@fish.tm] > Sent: Thursday, January 11, 2001 1:35 PM > To: php-general@lists.php.net > Subject: [PHP] Function -> Sending URL's > > > Hey there, > this is a strange one - I want to send a URL to a function that includes > varibles. Those variables should be taken from within the function - as in > the example below the link I want is: > > asdfasdf.php3?name=TEST , but that is not what I get as you can see. > > Does anybody know a way around this - The example is simpler than what I am > actually doing and the value of $company must come from the variable. > > Thanks, > Abe > > > > <? > function testPassVar($url) { > $name = "TEST"; > echo "<a href=\"$url\">Click</a>"; > } > > $url = 'asdfasdf.php3?name=$company'; > testPassVar($url); > echo "This is a $name"; > ?> > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >