RE: [PHP] Function -> Sending URL's
| From: | DanO | Date: | Thu, 11 Jan 2001 21:41:59 +0000 |
| Subject: | RE: [PHP] Function -> Sending URL's | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-34107@lists.php.net to get a copy of this message | ||
sorry, but i didn't fully understand what you are trying to do.
you can also pass 2 variables to the function:
<?
function testPassVar($url,$param) {
echo "<a href=";
echo $url;
echo "?name=";
echo $param;
echo ">Click Here</a>";
}
$script = 'asdfasdf.php3';
$company = 'TEST';
testPassVar($script,$company);
?>
-----Original Message-----
From: DanO [mailto:dano@informano.net]
Sent: Thursday, January 11, 2001 1:35 PM
To: Abe; php-general@lists.php.net
Subject: RE: [PHP] Function -> Sending URL's
you are assigning the variable within the function, then calling the
function with the variable.
this is a variable scoping issue.
try this:
<?
function testPassVar($url) {
echo "<a href=\"$url\">Click</a>";
}
$company = "TEST";
$url = 'asdfasdf.php3?name='.$company;
testPassVar($url);
?>
-----Original Message-----
From: Abe [mailto:abe@fish.tm]
Sent: Thursday, January 11, 2001 1:35 PM
To: php-general@lists.php.net
Subject: [PHP] Function -> Sending URL's
Hey there,
this is a strange one - I want to send a URL to a function that includes
varibles. Those variables should be taken from within the function - as in
the example below the link I want is:
asdfasdf.php3?name=TEST , but that is not what I get as you can see.
Does anybody know a way around this - The example is simpler than what I am
actually doing and the value of $company must come from the variable.
Thanks,
Abe
<?
function testPassVar($url) {
$name = "TEST";
echo "<a href=\"$url\">Click</a>";
}
$url = 'asdfasdf.php3?name=$company';
testPassVar($url);
echo "This is a $name";
?>
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