Re: If statement being ignored by PHP

well, probably doesn't work cause that if ( ) : thingie makes no sense? it's not: if (condition): code; endif; but: if (condition) { code; } also, get rid of the endif; stuff, cause that's not PHP either At 10:40 30-6-2000 -0400, Mike Gifford wrote:

Hello, I've got an a small script in which I would like to be able to first verify that a field isn't empty and if that field isn't empty, I'd like it to print a form. If the posting from the form is yes, I'd like to mail a message. Can someone tell me why my if statement is being ignored and why the message is posted directly before I have entered anything into the form? Here's the script: if ($semail!=""):

change to: if ($semail != "") {

$post=""; echo "<form method=\"POST\" action=\"send.php3\">"; echo "<input type=\"radio\" value=\"yes\" NAME=\"post\">Yes, please send my card!"; echo "<input type=\"radio\" value=\"no\" NAME=\"post\">No, I will try again."; echo "<input type=\"submit\" value=\"Submit\"></form><br>"; if ($post="yes"):

change to: if ($post == "yes") {

mail("$recipient <$remail>", "$sender has sent you a card", $message,"From: $semail \nReply-To: $semail\nX-Mailer: PHP3"); echo "Your card number $idnumber has been sent to $recipient."; endif;

change to: }

endif;

change to: }

Thanks! Mike --

Mike A. Gifford         OpenConcept Consulting

Mike@OpenConcept.On.Ca Http://www.OpenConcept.On.Ca Web Design, Hosting, Graphic Design & Site Promotion

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