Re: Accessing variables

> $i ++; > } while(!ereg("</V", $httpd_conf[$i])); > $i = $i++; > echo("#Removed $httpd_conf[$i]<BR>"); It seems that on the 3rd line of this block, you should put "$i = ++$i;". The assigment $i=$i++ is going to prevent the value of $i from incrementing (since the increment is done *after* the assign). HTH, Hans Lellelid ----- Original Message ----- From: "Ken N" <kenn@pcintelligent.com> To: <php-general@lists.php.net> Sent: Friday, June 30, 2000 9:31 AM Subject: [PHP] Accessing variables > Hi, > I have a strange question about variables. It seems like I can't > access my variable $i from a do/while that sits nested inside of a while > loop. If you look at the code below you'll see that I am printing line > number twice. What happnes is that The first echo(line) prints that line, > lets say 1234, then the second echo prints it bold just prints the same > line number 1234 seven times. however $i should be incremented every time. > The code is below maybe that'll make more sense. > > while(list($line_num, $line) = each($httpd_conf)) > { > if(ereg("@lime", $line)) > { > $i = ($line_num - 2); > echo("$line_num<BR>"); > do { > $line = "#Removed $httpd_conf[$i]"; > file://echo("#Removed $httpd_conf[$i]<BR>"); > echo("$line<BR>"); > echo("<B>$line_num</B><BR>"); > $i ++; > } while(!ereg("</V", $httpd_conf[$i])); > $i = $i++; > echo("#Removed $httpd_conf[$i]<BR>"); > } > fputs($httpd_new, $line); > } > > > Thanks > Ken N > > http://cleveland.lug.net/~rocket/ > > The answer is simple if you grant that ironies are like submarines; > dangerous only when submerged. > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net