Re: Simple String Replace Question
| From: | Simon Garner | Date: | Sun, 25 Feb 2001 23:32:21 +0000 |
| Subject: | Re: Simple String Replace Question | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-41615@lists.php.net to get a copy of this message | ||
From: "Jeff Oien" <jeff@webdesigns1.com>
> That almost works. The two \n in a row are on new lines.
> So it's
> \n
> \n
> intead of \n\n. If that makes any sense.
> Jeff Oien
No, that doesn't make any sense whatsoever :)
A \n *is* a new line. I can only guess you're getting confused because
there's \r's as well as \n's in the string. Try this:
<?php
$str = "abc\r\ndefg\r\n\r\nxyzpqr\r\njklmno";
$str = ereg_replace("([^\r\n])\r\n([^\r\n])", "\\1 \\2", $str);
echo $str;
?>
Or alternatively:
<?php
$str = "abc\r\ndefg\r\n\r\nxyzpqr\r\njklmno";
$str = ereg_replace("\r", "", $str);
$str = ereg_replace("([^\n])\n([^\n])", "\\1 \\2", $str);
echo $str;
?>
A CR is a carriage return, a LF is a line feed or newline. \r = CR, \n = LF.
Unix files use only LF (\n) for new lines, whereas MS DOS/Windows uses CRLF
(\r\n) and Mac uses just CR (\r).
Cheers
Simon Garner