Re: removing characters

I have just started with php a few days ago but in the book that I am reading it uses a foreach loop that is specifically for arrays. foreach($Area as $key=>$value) { your concatination string here } Rick At 04:45 PM 3/6/01 +1030, you wrote:

On Tue, 6 Mar 2001 15:50, rpruitt@mid-tn.com wrote: A problem of inexperience... I am trying to store an array in mysql. I obtain the array like so-- $partcount = count($Area);

             reset($Area);
             for ($i = 0; $i < $partcount; $i++){
               $key = key($Area);
               $val = $Area[$key];

$string1 .= $val . "\') or (Area=\'";

               next($Area);
             }

This results, with a bit of coaxing, in an array like this one -- +-----------------------------------------------------+

| Area                                                |

+-----------------------------------------------------+ | (Area='1') or (Area='2') or (Area='3') or (Area='') | +-----------------------------------------------------+ Everything is falling into place, *except* these last thirteen characters -- or (Area='') And that's what I'd like to eradicate. Tips, suggestions, especially outright code greatly appreciate. Thanks, Robert p.s.-- I have ordered the Friedl book on Regular Expressions. Hoping it will enlighten me for the future My suggestion would be to not create the empty reference in the firast place :-) Before starting your loop (but after checking there is something to work with) use the first element of the arra to create the (Area='1') then you can loop through the rest of the array, starting with $i = 1 and create or (Area='$val') --

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