Re: HELP! tempnam(); function confusion

"C. Marcera" wrote: > > ### Why does this code: > > $tmpfname = tempnam( "/tmp", "PErq" ); > echo "file made '$tmpfname'<BR>"; > echo "$tmpfname<BR>"; > $tempfile = fopen( "$tmpfname", "w" ); > echo "file open '$tempfile'<BR>"; > $num = count( $query_results ); > for( $i=0; $i<$num; $i++ ) { > fwrite( "$tempfile", > "\t<LI<STRONG>$query_results[$i]</STRONG><LI>\r" ); > echo "file written to '$tempfile'<BR>"; > } > fclose( "$tempfile" ); > echo "file closed '$tempfile'<BR>"; > > ### produce this: > > file made '/tmp/PErq000730' > /tmp/PErq000730 > file open '16' > file written to '16' > file closed '16' > > Where is the 16 coming from? when I place a "/" or "/tmp" in the fopen() > function then it will display the '/tmp/PErq000730', but the path is wrong > then (i.e. Warning: fopen("/tmp//tmp/PErq000732","w") - No such file or > directory) > > Is there another way to return the filename with tempnam()? Any help would > be great... thanks in advance! > Hi! tempnam() returns new filename as string, it's not actual file. And this string (in this case $tmpfname) you can use as filename for fopen(). fopen() returns file handle ($tempfile) as integer. This is the 16 in this case. Maybe this helps. -- Pavel a.k.a. Papi