Re: sorting results of opendir()

Here's one way: $dir = opendir('.'); unset($FileList); while ($file=readdir($dir)) { if($file!= '.' && $file != '..') { $FileList[] = $file; } } sort $FileList; reset($FileList); while(list(, $F) = each($FileList)) { echo "$F<br>\n"; } If you're using PHP4, you can replace everything after the sort($FileList) with the more compact: foreach($FileList as $F) { echo "$F<br>\n"; } See http://www.php.net/manual/en/function.sort.php for more info on sorting arrays. - steve At 1:05 PM -0500 7/9/01, kmurrah wrote:

Greetings. I need to read the contents of a directory, sort it alphabetically, and display it .... i'm doing find on the reading and displaying, but can someone help me with the sort? $dir = opendir("."); while ($file=readdir($dir)) { if($file!= "." && $file != "..") { echo("$file<br>"); } }

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