Re: Removing All Instances From An Array

well.... I don't know much but maybe I can get you started on the right path... unset($array[$picked]); will take away that key and value from the array... you can have a loop like $val = $array[$picked]; $list = each($array); while($list[0]) { if($list[1] == $val) { $key = $list[0]; unset($array[$key]); } $list = each($array); } There may be a few bugs there, and there probably is a more efficient way of writing that... but you get the idea, hopefully :) Ed ""Andrew"" <fisherres@msn.com> wrote in message news:004501bfec40$ff2462e0$4336173f@8vrta... > Hello, > > 1. I have an array $array = array (1,2,3,3,3,4,5,6,7,8,9,9); > 2. The variable $picked has the value 2. > 3. If I print the value of $array[$picked] I see the number three. > 4. Well instead of printing the number three I want to remove all instances > of 3 from the array. So, my array should look like $array = array > (1,2,4,5,6,7,8,9,9); > > Basically, whatever the value of $array[picked] is, I want to remove all > instances of that value from the array. > > Andrew > digi-FX > ------------------------------- > http://www.digi-FX.net > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >