Re: Replacing datafile with array

works like a charm.... just initializet the $retVal function... $retVal = array(); rest of script here.... "Daniel alsén" <d@mindbash.com> wrote in message news:PGEGIELINOCCEHLENIOJKENGCCAA.d@mindbash.com... > Hi, > > i am trying to replace a datafile wich contains the contents of a directory > with an array. > I am reading the directory and am trying to pass the value to an array. What > am i doing wrong? Shouldn´t $retVal contain the direcory info? > > Also, is there a way to use the content of an array without getting the word > 'Array' at the start? > > $handle=opendir('.'); > while (false !== ($file = readdir($handle))) > > if ($file != "." && $file != ".." && > ereg(".jpg",$file)) { > > $retVal[count($retVal)] = $file; > > } > > # Daniel Alsén | www.mindbash.com # > # d@mindbash.com | +46 704 86 14 92 # > # ICQ: 63006462 | # >