Re: Re: Replacing datafile with array

Man, you can't do echo Array! you have to walk through an array! dump the array and see its content via: var_dump($retVal) for example, refer yourself to the array functions in PHP's manual, "Daniel alsén" <d@mindbash.com> wrote in message news:PGEGIELINOCCEHLENIOJAENHCCAA.d@mindbash.com... > Hmm... > > it still doesn´t work. > > If i echo $retVal i just get the word 'Array' (the same number of times that > the number of files in the directory). > > If i echo $file i get the file listing...however, it doesn´t pass on the > content to the rest of my script. > > Maybe someone could help me out with the whole script? I downloaded this > from some script archive and it works if i use the list.photos datafile. But > i don´t want to change that file every time a new photo is uploaded. > I am trying to read the directory and use the directory handle listing > instead. > > If anyone wants to help me out making this databasedriven instead youre very > welcome :) > > <?PHP > > $retVal = array (); > //Load Directory Into Array > $handle=opendir('.'); > while (false !== ($file = readdir($handle))) > > if ($file != "." && $file != ".." && > ereg(".jpg",$file)) { > > $retVal [count($retVal)] = $file; > > echo "$retVal <br>\n"; > > } > > //initialize variables > //$data_file = "list.photos"; > $thumbnail_dir = "thumbs/"; > $num_rows = 3; > $photos_per_row = 3; > $photos = file($retVal); //$retVal used to be $data_file > $total_photos = sizeof($photos); > $photos_per_page = $num_rows * $photos_per_row; > //check to see if the start variable exists in the URL. > //If not, then the user is on the first page - set start to 0 > if(!isSet($start)){ > $start = 0; > } > //init i to where it needs to start in the photos array > $i = $start; > $prev_start = $start - $photos_per_page; > $next_start = $start + $photos_per_page; > > > for ($row=0; $row < $num_rows; $row++){ > print("<tr>\n"); > for ($col=0; $col < $photos_per_row; $col++){ > if($i < $total_photos){ > $thumbnail = $thumbnail_dir.trim($photos[$i]); > $thumb_image_size = getimagesize($thumbnail); > $image_size = getimagesize(trim($photos[$i])); > print("<td align=\"center\"> > <a > href=\"javascript:photo_open('photo_display.php?photo=".trim($photos[$i])."' > > ,'".$image_size[0]."','".$image_size[1]."');\"><img > src=\"".$thumbnail."\" > ".$thumb_image_size[3]." border=\"0\"></a></td>\n"); > } else { > print("<td></td>\n"); > } > $i++; > } > print("</tr>\n"); > } > > > //Clean up directory array > closedir($handle); > return $retVal; > > > //end table > ?> > > > -----Original Message----- > > From: _lallous [mailto:elias_bachaalany@yahoo.com] > > Sent: den 18 september 2001 13:46 > > To: php-general@lists.php.net > > Subject: [PHP] Re: Replacing datafile with array > > > > > > works like a charm.... > > > > just initializet the $retVal function... > > > > $retVal = array(); > > rest of script here.... >