RE: [PHP] Making a string from an Array
| From: | Taylor, Stewart | Date: | Thu, 25 Oct 2001 15:34:40 +0000 |
| Subject: | RE: [PHP] Making a string from an Array | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-72289@lists.php.net to get a copy of this message | ||
$ignored = "";
$include = "";
<snip>
{
$ignored.= $words[$i];
}
else
{
$included.= $words[$i];
-Stewart
-----Original Message-----
From: Sam [mailto:Sam@dragoman.co.uk]
Sent: 25 October 2001 16:18
To: 'php'
Subject: [PHP] Making a string from an Array
Hi all,
this may be an easy question, but I'm stuck...
how can this,
$words = explode(" ", $keywordText);
for ( $i = 0; $i < count( $words ); $i++ )
{
if ($words[$i]=="on" OR $words[$i]=="the" OR $words[$i]=="in"
OR$words[$i]=="at" OR $words[$i]=="is" OR $words[$i]=="it")
{
$ignored[] = $words[$i];
}
else
{
$included[] = $words[$i];
}
}
How can I make $included and $ignored a string instead of an array.
Thanks
Sam Rose
p.s. Also I'm only on the digest, so if you could reply directly to me as
well, that would be a bonus.