Re: Making a string from an Array
| From: | Mike Frazer | Date: | Thu, 25 Oct 2001 16:38:42 +0000 |
| Subject: | Re: Making a string from an Array | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-72300@lists.php.net to get a copy of this message | ||
A small addition:
the code below would make a string, but it would be a single word (no spaces
or other word boundaries). Use this instead:
$ignored .= " " . $words[$i];
That inserts a space before each additional word. Unfortunately it also
adds a space at the beginning but you can get rid of that after the
processing is done.
Mike
"Stewart Taylor" <Stewart.Taylor@uk.thalesgroup.com> wrote in message
news:2B25A9C95DC8D411BBE500508BB19239515E31@ntslxch1.int.rdel.co.uk...
> $ignored = "";
> $include = "";
>
> <snip>
> {
> $ignored.= $words[$i];
> }
> else
> {
> $included.= $words[$i];
>
> -Stewart
> -----Original Message-----
> From: Sam [mailto:Sam@dragoman.co.uk]
> Sent: 25 October 2001 16:18
> To: 'php'
> Subject: [PHP] Making a string from an Array
>
>
> Hi all,
> this may be an easy question, but I'm stuck...
>
> how can this,
>
> $words = explode(" ", $keywordText);
>
> for ( $i = 0; $i < count( $words ); $i++ )
> {
> if ($words[$i]=="on" OR $words[$i]=="the" OR $words[$i]=="in"
> OR$words[$i]=="at" OR $words[$i]=="is" OR $words[$i]=="it")
> {
> $ignored[] = $words[$i];
> }
> else
> {
> $included[] = $words[$i];
> }
> }
>
> How can I make $included and $ignored a string instead of an array.
>
> Thanks
> Sam Rose
>
> p.s. Also I'm only on the digest, so if you could reply directly to me as
> well, that would be a bonus.