Re: Call a script as an image--Is this right?

From: Date: Fri, 21 Jul 2000 04:03:41 +0000
Subject: Re: Call a script as an image--Is this right?
References: 1 2 3  Groups: php.general 
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Is this the way it suppose to be? I tried but it still shows broken image Thank you again? <? include ("user.php"); $imgfile="http://mydomain.com/images/1.gif"; header("Content-type: image/$imgtype"); header("Content-Length: " . filesize($imgfile)); @readfile($imgfile); $handler=@mysql_connect($db_server,$db_username,$db_passwort); @mysql_select_db($db_database,$handler); $zeit = time(); $ip = getenv(REMOTE_ADDR); $file = $PHP_SELF; $result=@mysql_query("INSERT INTO $db_table VALUES ('$zeit','$ip','$file')",$handler); @mysql_close(); ?> John wrote: > > Thank you Andreas. > > Actually I am not tracking users IP adress. > The script is a part of who's online script. > I use a remote service(web based email) and I want to include those > users also in my site to show who's online. > > Thanx again > > Andreas Pour wrote: > > > > John wrote: > > > > > > Call a script as an image from a remote server > > > > > > Hi, > > > > > > In the below code(let's call it count.php) I want to insert an image. > > > I want to call this script from a remote server as an image and instead > > > of showing a broken image link, I want it to show an image. > > > > > > <img > > > src="http://mydomain,com/count.php"> > > > > > > Is there any way I can do this ? > > > > > > Thanks in advance. > > > > > > John > > > > > > ################## > > > Count.php > > > ################## > > > //<?echo "<img > > > src=\"http://mydomain.com/images/1.gif\">";?> > > > <? > > > include ("user.php"); > > > $handler=@mysql_connect($db_server,$db_username,$db_passwort); > > > @mysql_select_db($db_database,$handler); > > > $zeit = time(); > > > $ip = getenv(REMOTE_ADDR); > > > $file = $PHP_SELF; > > > $result=@mysql_query("INSERT INTO $db_table VALUES > > > ('$zeit','$ip','$file')",$handler); > > > > Although I can't approve of tracking user's IP addresses like this, just > > add the lines > > > > header("Content-type: image/$imgtype"); > > header("Content-Length: " . filesize($imgfile)); > > @readfile($imgfile); > > > > Ciao, > > > > Andreas > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > > For additional commands, e-mail: php-general-help@lists.php.net > > To contact the list administrators, e-mail: php-list-admin@lists.php.net > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net

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