Re: Call a script as an image--Is this right?

Thank you very much. It works flawlessly. Best Regards, John Andreas Pour wrote: > > John wrote: > > > > Is this the way it suppose to be? > > I tried but it still shows broken image > > Thank you again? > > Nope, not quite there yet ;-). > > > > > <? > > include ("user.php"); > > > > $imgfile="http://mydomain.com/images/1.gif"; > > $imgfile = "/local/path/on/your/server/to/the/image/file"; > > Likely something like "/www/images/l.gif". > > Ciao, > > Andreas > > > > > header("Content-type: image/$imgtype"); > > header("Content-Length: " . filesize($imgfile)); > > @readfile($imgfile); > > > > $handler=@mysql_connect($db_server,$db_username,$db_passwort); > > @mysql_select_db($db_database,$handler); > > > > $zeit = time(); > > $ip = getenv(REMOTE_ADDR); > > $file = $PHP_SELF; > > > > $result=@mysql_query("INSERT INTO $db_table VALUES > > ('$zeit','$ip','$file')",$handler); > > > > @mysql_close(); > > > > ?> > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net