Re: Re: Re: How do I convert from perl to php?

From: Date: Tue, 20 Nov 2001 22:37:02 +0000
Subject: Re: Re: Re: How do I convert from perl to php?
References: 1  Groups: php.general 
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No, but this: $required = array('name','address','phone'); foreach( $required as $key ) { if( empty($HTTP_POST_VARS[$key]) ) { print("Sorry, you left key empty."); } } should work. On Tue, 20 Nov 2001, Brandon Lamb wrote: > What about this? > > $required = array('name','address','phone'); > while ( list($key, $value) = each ($required) ) { > if ( empty($value) ) { > print("Sorry, you left $key empty."); > } > } > > ----- Original Message ----- > From: "Philip Hallstrom" <philip@adhesivemedia.com> > Cc: <php-general@lists.php.net> > Sent: Tuesday, November 20, 2001 2:22 PM > Subject: Re: Re: How do I convert from perl to php? > > > You could do something like this... there are lots of ways to validate > your data... > > while( list($key, $value) = each($HTTP_POST_VARS) ) { > if( empty($value) ) { > print("Sorry, you left $key empty."); > } > } > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >

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