RE: How do I convert from perl to php?

$required = array($name, $address, $phone); foreach($required as $value) { if (!$value) echo("You left one empty."); } well that's how I'd do exactly that, although if you know the variables then why not just... if (!$name || !$address || !$phone) echo("You left one empty"); that's quicker, unless you need the values in a hash list for some other reason. Tim ---------- From: digital1@olypen.com [SMTP:digital1@olypen.com] Sent: 20 November 2001 22:10 To: php-general@lists.php.net Subject: How do I convert from perl to php? I am a perl user trying to convert to php how would i turn this perl into php? use CGI; $name = param(name); $address = param(address); $phone = param(phone); @required = qw( name address phone ); foreach $key($required) { if (!$$key) { &out("You left one empty."); } } ?? --------------------------------------------- This message was sent using OlyPen's WebMail. http://www.olypen.com The original message was received at Tue, 20 Nov 2001 14:05:28 -0800 from mail.olypen.com [208.200.248.2] ----- The following addresses had permanent fatal errors ----- <php-general@lists.php.ne> (reason: 550 Host unknown) ----- Transcript of session follows ----- 550 5.1.2 <php-general@lists.php.ne>... Host unknown (Name server: lists.php.ne: host not found)<<File: ATT27355.TXT>><<Message: Converting from being a perl user>>