Re: Re: Anyone Up?

I think you'll need something like this: VALUE=\'Your Name1\' / /single quote marks I believe (and I certainly could be wrong). otherwise it'll truncate at 'Your' of course, if this is what you want... Hugh ----- Original Message ----- From: "Luke Welling" <luke@tangledweb.com.au> To: <php-general@lists.php.net> Sent: Thursday, January 31, 2002 11:50 PM Subject: [PHP] Re: Anyone Up? > > "Jtjohnston" <taylorjo@collegesherbrooke.qc.ca> wrote in message > news:3C5A44F5.762CDFB4@collegesherbrooke.qc.ca... > > Luke is that 6:47 pm tomorrow? :) You lost an entire day! > > Enough Oz Jokes. Here is my predicament in Canada :-) > > > > $varname = "Check".$i; > > > > $varname = "Check1" but I want $varname = "Your Name1" to "Your > > Name12". > > > > One more try? :) > > > > <INPUT TYPE="checkbox" NAME="Check1" VALUE="Your > > Name1"> > > <INPUT TYPE="checkbox" NAME="Check2" VALUE="Your > > Name2"> > > <INPUT TYPE="checkbox" NAME="Check3" VALUE="Your > > Name3"> > > etc. > > > > for ($i = 1; $i <= $NMax; $i++) > > { > > #$varname = "$Check".$i; > > $varname = "Check".$i > > #echo $varname; > > if ($varname) > > echo "$varname = $i<br>"; > > } > > In that case it is easy, I did not know that the ids were just 1 to 12, I > thought they could be anything spat out by the database. > > How about something like this: > > for ($i = 1; $i <= $NMax; $i++) > { > $varname = "Check".$i > if (isset($$varname) > echo $$varname."<br>"; > } > > Luke Welling. > -- > PHP and MySQL Web Development > by Luke Welling and Laura Thomson > http://www.amazon.com/exec/obidos/ASIN/0672317842 > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >