Re: PHP function inside a regex - possible?
| From: | Andreas Pour | Date: | Thu, 01 Jun 2000 18:56:52 +0000 |
| Subject: | Re: PHP function inside a regex - possible? | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-853@lists.php.net to get a copy of this message | ||
kev wrote:
>
> This isn't giving the desired results though when there is more than one term
> to be modified, eg with this string:
>
> $text = "Turn <B>term 1</B> and <B>term 2</B> to a link";
>
> It turns everything in between the first <B> and the last </B> into a link!
>
> How do I guard against that, but ensure that it still modifies every bolded
> term?
Hi,
This is just a preg issue. You need to make your .* stingy:
$newtext = preg_replace("/<B>(.*?)<\/B>/e", "\"<A href=\"
. '\\1' .
\"><B>\" . '\\1' . \"</B></A>\"", $text );
Ciao,
Andreas
> thanks,
>
> - Kev
>
> Andreas Pour wrote:
>
> > Hi, Kevin,
> >
> > As to your example, you have to have the replacement string be suitable
> > for an "echo" statement, I think. The following works, anyway:
> >
> > $newtext = preg_replace("/(<B>(.*)<\/B>)/e", "\"<A
> > href=\" . '\\2' .
> > \"><B>\" .
> > '\\2' . \"</B></A>\"", $text );
> >
> > Good luck,
> >
> > Andreas
> >
> > kev wrote:
> > >
> > > Zak McGregor wrote:
> > >
> > > > In php 3.x, no. In php 4.x try:
> > > > preg_replace("/<B>(.*)?<\/B>/", "<A
> > > >
> > > > HREF=\"whatever.php3?search=".urlencode('\\1')."\">".'\\1'."<\/A>");
> > > >
> > >
> > > I'm using PHP4.
> > > I don't understand how that could work, how will it know what '\\1' is
> > > in the urlencode() ? The function has not even been entered at that
> > > point, so surely urlencode('\\1') will just equate literally to
> > > '\\1'
> > > urlencode()ed.
> > >
> > > Anyway, I tried this little example as a starting point to build up to
> > > the full thing eventually:
> > >
> > > $text = "Turn <B>bold</B> to a link";
> > >
> > > $newtext = preg_replace( "/<B>(.*)?<\/B>/e",
> > > "<A href=\\1><B>\\1</B></A>",
> > > $text );
> > >
> > > echo "\$text = $text<BR>";
> > > echo "\$newtext = $newtext<BR>";
> > >
> > > Please try this example, and you'll see it doesn't work. Can you see
> > > what's wrong with it?
> > > Also, is question mark (?) needed?
> > > In Perl, I use $1 for a back-reference, is \\1 the PCRE equivalent?
> > >
> > > thanks,
> > >
> > > - Kev
>