Re: return

But to answer your question The purpose of return, is to "return" a value.. function test($var) { return addslashes($var); } $foo = "Yes, I'am Very Awsome"; $foo = test($foo); echo($foo); // echo's, Yes I\'am Very Awsome Understand? ----- Original Message ----- From: "Rasmus Lerdorf" <rasmus@lerdorf.ca> To: "Gary" <garyb10@earthlink.net> Cc: <php-general@lists.php.net> Sent: Sunday, March 31, 2002 11:43 PM Subject: Re: [PHP] return > Nope, that code makes no sense. $_POST is an array containing the POST > variables. You make a copy of that array an put it in $foo thereby > overwriting the passed in $foo. Then you return $$foo which actually ends > up returning a variable named $Array. It does not look like you have a > $Array variable in scope, and it is surely not what the misguided coder > behind this code was trying to achieve. In short, this is completely > bogus. > > -Rasmus > > On Sun, 31 Mar 2002, Gary wrote: > > > Can someone explain to me the reason for using return. > > > > function _getValue($foo) > > { > > $foo = $_POST; > > return ${$foo}; > > } > > > > TIA > > Gary > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > >