Re: return

Eric, Isnt there really no need for the 'return' though? $test ($var) { addslashes($var) } $foo = "He's dreaming"; $foo = test($foo); print($foo); //should also print He\'s dreaming Am I incorrect in thinking this? -Jordan K. Martin http://www.newimagedesign.com Eric Coleman <eric.coleman@zaireweb.com> wrote in message news:018e01c1d93d$cd404be0$0201a8c0@zaireweb... > But to answer your question > > The purpose of return, is to "return" a value.. > > function test($var) > { > return addslashes($var); > } > > $foo = "Yes, I'am Very Awsome"; > $foo = test($foo); > echo($foo); > // echo's, Yes I\'am Very Awsome > > Understand? > > ----- Original Message ----- > From: "Rasmus Lerdorf" <rasmus@lerdorf.ca> > To: "Gary" <garyb10@earthlink.net> > Cc: <php-general@lists.php.net> > Sent: Sunday, March 31, 2002 11:43 PM > Subject: Re: [PHP] return > > > > Nope, that code makes no sense. $_POST is an array containing the POST > > variables. You make a copy of that array an put it in $foo thereby > > overwriting the passed in $foo. Then you return $$foo which actually ends > > up returning a variable named $Array. It does not look like you have a > > $Array variable in scope, and it is surely not what the misguided coder > > behind this code was trying to achieve. In short, this is completely > > bogus. > > > > -Rasmus > > > > On Sun, 31 Mar 2002, Gary wrote: > > > > > Can someone explain to me the reason for using return. > > > > > > function _getValue($foo) > > > { > > > $foo = $_POST; > > > return ${$foo}; > > > } > > > > > > TIA > > > Gary > > > > > > > > > -- > > > PHP General Mailing List (http://www.php.net/) > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > >