RE: [PHP] simplify if/then statement

I'd do something similar to this, along with putting all states in an array to make sure $state is actually a state (in_array). And maybe you want to add guam :) a) be sure $state is set, else load default b) be sure $state is not bogus, else yell at them c) be sure the $state file exists, if so, include it else houston we have a problem Regards, Philip Olson On Sat, 27 Apr 2002, Stuart Dallas wrote: > $incfilename = "Calc".$state.".class.inc"; > if (file_exists($incfilename)) > include($incfilename); > else > echo "Please select a State.<br>\n"; > > -- > Stuart > > -----Original Message----- > From: Jim Long [mailto:jim@jimlong.net] > Sent: 27 April 2002 20:00 > To: php > Subject: [PHP] simplify if/then statement > > > Hi, > > I've got the following statement for a state options menu. > How can this be expressed in a simple manner for all 52 states? > > > //choose state > > if ($state == "AL") { > > // include class > include("CalcAL.class.inc"); > } > > else if ($state == "AR") { > > // include class > include("CalcAR.class.inc"); > } > > else if ($state == "AZ") { > > // include class > include("CalcAZ.class.inc"); > } > > else{ > echo "Please select a State.<br>\n"; > } > > Thank You Very Much, > > Jim Long > -- > http://jimlong.net/web > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >