RE: [PHP] simplify if/then statement

On Sat, 27 Apr 2002, Philip Olson wrote: > I'd do something similar to this, along with putting all states in an > array to make sure $state is actually a state (in_array). And maybe you > want to add guam :) As an early Christmas present, here's the array (to save the OP some typing - I'm posting this to the list because I use it a lot and assume it'd be handy for others too). Uses USPS 2-letter abbreviations and includes territories. $states = array( 'AK' => 'Alaska', 'AL' => 'Alabama', 'AR' => 'Arkansas', 'AS' => 'American Samoa', 'AZ' => 'Arizona', 'CA' => 'California', 'CO' => 'Colorado', 'CT' => 'Connecticut', 'DC' => 'District of Columbia', 'DE' => 'Delaware', 'FL' => 'Florida', 'GA' => 'Georgia', 'GU' => 'Guam', 'HI' => 'Hawaii', 'IA' => 'Iowa', 'ID' => 'Idaho', 'IL' => 'Illinois', 'IN' => 'Indiana', 'KS' => 'Kansas', 'KY' => 'Kentucky', 'LA' => 'Louisiana', 'MA' => 'Massachusetts', 'MD' => 'Maryland', 'ME' => 'Maine', 'MH' => 'Marshall Islands', 'MI' => 'Michigan', 'MN' => 'Minnesota', 'MO' => 'Missouri', 'MP' => 'Northern Mariana Islands', 'MS' => 'Mississippi', 'MT' => 'Montana', 'NC' => 'North Carolina', 'ND' => 'North Dakota', 'NE' => 'Nebraska', 'NH' => 'New Hampshire', 'NJ' => 'New Jersey', 'NM' => 'New Mexico', 'NV' => 'Nevada', 'NY' => 'New York', 'OH' => 'Ohio', 'OK' => 'Oklahoma', 'OR' => 'Oregon', 'PA' => 'Pennsylvania', 'PR' => 'Puerto Rico', 'RI' => 'Rhode Island', 'SC' => 'South Carolina', 'SD' => 'South Dakota', 'TN' => 'Tennessee', 'TX' => 'Texas', 'UT' => 'Utah', 'VA' => 'Virginia', 'VI' => 'Virgin Islands (U.S.)', 'VT' => 'Vermont', 'WA' => 'Washington', 'WI' => 'Wisconsin', 'WV' => 'West Virginia', 'WY' => 'Wyoming'); miguel