RE: [PHP] Stupid question

When I run: $number = 0.023884057998657; echo round($number, 3); echo number_format($number, 3); Both function output "0.024", both functions round the last digit. This is contrary to the example in the manual which shows this: $number = 1234.5678; // english notation without thousands seperator $english_format_number = number_format($number, 2, '.', ''); // 1234.56 http://www.php.net/manual/en/function.number-format.php My output for the above is: 1234.57 not 1234.56 I'm using PHP Version 4.0.6 I would consider using the following to truncate a number if you do not want to round. There may be a better way, but this seems to work fine. substr($number, 0,strpos($number, ".")+4); Robert V. Zwink http://www.zwink.net -----Original Message----- From: Craig Vincent [mailto:2bunnyhop@rogers.com] Sent: Thursday, May 02, 2002 5:54 AM To: Liam MacKenzie; php-general@lists.php.net Subject: RE: [PHP] Stupid question > I have a script that outputs this: > 0.023884057998657 > > What's the command to make it shrink down to this: > 0.023 > > > I thought it was eregi() something, but I forgot. sorry It depends on what you need. If you want to round the number off to 3 decimal points use the round() function. However if you don't want to round and instead just want to truncate the number, the number_format() function would be what you need. Sincerely, Craig Vincent -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php