Re: $ref =& $this;

Hello Derick, Monday, October 3, 2005, 3:09:22 PM, you wrote: > Hello, > Dmitry committed a fix earlier to ignore the & in the statement above. I > think this is not a good thing to do as it's simply conceptually wrong. > The first thing is that ignoring syntax without issuing a warning is > dubious because people might think it does actually work, and secondly > because I think that the code above is wrong anyway - somewhat in the > same way that "$this = new foo();" is wrong. > There is never any need to assign $this by reference, nor to pass it by > reference to a function as it's an object anyway, making the references > pointless - I would even go as far as disallowing passing $this by > references to a function - where the reference has to be ignored again, > otherwise it allows you to chantge $this to a different object with: > class Foo { > function byRef(&$f) { > $f = new Bar(); > } > function modifyThis() { > $this->byRef($this); > } > } > I think we should prevent people from writing syntax like this, as it is > not obvious what is going to happen. This means that we should revert > Dmitry's patch. Same here. Best regards, Marcus