Re: php7- dropping the $ from the variable name - rfc

On Thu, Sep 18, 2008 at 11:30:37AM -0700, Ionut Gabriel Stan wrote: > Actually, I somehow understand what he wants, considering we'll soon have lambdas and > closures. I mean, in case of javascript a variable can hold as well a function as it can hold > anything else. > Anyway, I don't think this is the case for PHP. I do find it ugly to write $function(), > but I guess I'll live with it as I did until now. So if you drop the '$' the way that you call a function referenced in variable 'funref' is not: $funref() but funref() However: the PHP parser will take that to be a call to a function named 'funref'. So you need to change the syntax to, perhaps, something like C: (funref)() I can't see people understanding that. Stick with what we have. -- Alain Williams Linux Consultant - Mail systems, Web sites, Networking, Programmer, IT Lecturer. +44 (0) 787 668 0256 http://www.phcomp.co.uk/ Parliament Hill Computers Ltd. Registration Information: http://www.phcomp.co.uk/contact.php Chairman of UKUUG: http://www.ukuug.org/ #include <std_disclaimer.h>