Re: Re: $arr = array('Hello', 'world'); $arr();

On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena <felipensp@gmail.com> wrote: > class foo { >   public function __construct() { >      $this->bar = function () { return 1; }; >      // $this->bar(); // error >      $x = $this->bar; >      $x(); // ok > >      $this->bar = array($this, 'baz'); >      // $this->bar(); // error >      $x = $this->bar; >      $x(); // ok >   } >   public function baz() { >      echo 'baz'; >    } > } What he meant was passing an existing method as a callback if you don't invoke it, i.e. passing "$this->bar" instead of array($this, "bar"). I don't know how hard it'd be to achieve, but it sounds pretty awesome to me. Cheers -- Jordi Boggiano @seldaek :: http://seld.be/