Re: Re: $arr = array('Hello', 'world'); $arr();

Will this work: array('foo', 'bar')('arg1', 'arg2') ? On Wed, Jun 8, 2011 at 3:48 PM, Christian Kaps <christian.kaps@mohiva.com> wrote: > On Wed, 8 Jun 2011 15:39:59 +0200, Jordi Boggiano wrote: >> >> On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena <felipensp@gmail.com> wrote: >>> >>> class foo { >>>   public function __construct() { >>>      $this->bar = function () { return 1; }; >>>      // $this->bar(); // error >>>      $x = $this->bar; >>>      $x(); // ok >>> >>>      $this->bar = array($this, 'baz'); >>>      // $this->bar(); // error >>>      $x = $this->bar; >>>      $x(); // ok >>>   } >>>   public function baz() { >>>      echo 'baz'; >>>    } >>> } >> >> What he meant was passing an existing method as a callback if you >> don't invoke it, i.e. passing "$this->bar" instead of array($this, >> "bar"). I don't know how hard it'd be to achieve, but it sounds pretty >> awesome to me. >> >> Cheers > > Yep, just what I meant. > > -- > PHP Internals - PHP Runtime Development Mailing List > To unsubscribe, visit: http://www.php.net/unsub.php > >