Re: Add a new flag for json_encode

> On 4 Nov 2014, at 20:06, Jakub Zelenka <bukka@php.net> wrote: > > That's a good point. However I still think that there are more advantages for making this > the default. I like mainly the idea that json_decode(json_encode($a)) = $a for all floats which is > not the case at the moment. Also it allow some other things that were mentioned before. It won’t be with or without your changes, as JSON can’t encode Infinity or NaN. Also, I don’t think it matters. PHP isn’t a strictly-typed language where there’s an important difference between float(7000) and int(7000). They act exactly the same in all contexts. There’s no benefit to this change that I can see within PHP (perhaps with other languages that have weird JSON parsers), and it causes problems as I’ve said above. Thus, I can’t support it being a default. -- Andrea Faulds http://ajf.me/