Re: [DISCUSSION] Make empty() a Variadic

> On 13 Feb 2015, at 11:16, Andrea Faulds <ajf@ajf.me> wrote: > > Hey, > >> On 13 Feb 2015, at 07:28, Michael Wallner <mike@php.net> wrote: >> >> On 12/02/15 19:55, Thomas Punt wrote: >> >>> I'd like to propose to make empty() a variadic, where if any >>> arguments passed in are considered empty, then false is returned >> >> Should that read "if any arguments passed in are considered *NOT* empty, >> then false is returned”? > > No, I think it’s correct, if confusingly phrased. I believe Thomas is proposing variadic > empty() where TRUE is returned if any of its arguments are empty, otherwise FALSE. So, empty($a, $b, > $c) would be equivalent to empty($a) || empty($b) || empty($c), much like isset($a, $b, $c) is > equivalent to (and implemented as) isset($a) && isset($b) && isset($c). Wait, I think I made a mistake. * Thomas proposed "if any arguments passed in are considered empty, then false is returned”, i.e. !(empty($a) || empty($b) || empty($c)) if his words are taken literally. This doesn’t make much sense, I think it was a mistake. * You suggested he may have meant "if any arguments passed in are considered *NOT* empty, then false is returned”, i.e. (empty($a) && empty($b) && empty($c)) * I assume Thomas actually meant “where if any arguments passed in are considered empty, then *true* is returned”, i.e. (empty($a) || empty($b) || empty($c)) Sorry for the confusion. I think the || behaviour is the most useful, as it’s the analogue of isset’s. So !empty($a, $b, $c) would work similarly to isset($a, $b, $c), and similarly, !isset($a, $b, $c) would work similarly to empty($a, $b, $c). But that’s just my opinion. :) -- Andrea Faulds http://ajf.me/