Re: protected __call() question

Hello Ferdinand, that seems to be the current argument - but we have changed otehr places like that already so we should make this feature request or even bug. marcus Monday, April 5, 2004, 1:18:57 PM, you wrote: > On 5 Apr 2004 at 11:23, Derick Rethans wrote: >> It is called from a public function, how can that be outside of the >> class' point of view? >> >> Derick > Ah, now I understand your point. But __call() is called by the engine, > not by setup(), so it is the outside world.... > Class CallMe > { > public function setup() > { > $this->fakeMethod(); > } > protected function __call($method, $params) > { > echo 'you called CallMe::'.$method."\n"; > } > } > -- > Ferdinand Beyer > <fb@fbeyer.com> -- Best regards, Marcus mailto:helly@php.net