Re: Add spaceship assignment operator

Morning Nikita, Thanks for all your hard work. Since consistency is one of our main focuses, I move that the discussion period for this extremely important work is moved forward by one week. All in favour, say I. Cheers Joe On Thu, Mar 24, 2016 at 5:56 PM, Bob Weinand <bobwei9@hotmail.com> wrote: > > > Am 24.3.2016 um 18:50 schrieb Nikita Popov <nikita.ppv@gmail.com>: > > > > Hi internals! > > > > For consistency, we should add a spaceship assignment operator: > > > > $a <=>= $b; > > // same as > > $a = ($a <=> $b); > > > > Additionally, we should add an is-identical assignment operator: > > > > $a ==== $b; > > // same as > > $a = ($a === $b); > > > > Thank you for taking this proposal under consideration. > > > > Regards, > > Nikita > > I see a problem with that … It’d be impossible to make it consistent with > is-equal comparison… > > === is already is-identical comparison. So, no symbol for the is-equal > assignment operator left. > > As long as you don’t have any better suggestion, I’m sorry, but -1 on that. > > Bob > > > > >