Re: Add spaceship assignment operator

Hi Nikita, On Fri, Mar 25, 2016 at 12:50 AM, Nikita Popov <nikita.ppv@gmail.com> wrote: > Hi internals! > > For consistency, we should add a spaceship assignment operator: > > $a <=>= $b; > // same as > $a = ($a <=> $b); I miserably fail to imagine any use case for this. > Additionally, we should add an is-identical assignment operator: > > $a ==== $b; > // same as > $a = ($a === $b); > > Thank you for taking this proposal under consideration. Besides the comment about that one from Sara, I also fail to remotely imagine why one would need that. In short, yes, it is consistent but it is really unreadable, at best. -- Pierre @pierrejoye | http://www.libgd.org