note 72015 added to function.mysqli-stmt-bind-result

In response to 'matti at withoutthis dot keller dot com', Your function works great but there is one thing you should clear up when you say the following: '# But beware! when using the fetch in a loop, always COPY $result or else you might # end with all the same values because of the references'. Can someone explain how exactly to COPY the contents of an array that is referenced? Myself, I am having a little trouble. In my WHILE LOOP that fetches a result set I have the following: <?php $temp = $result; ?> This is my understanding of copying an array, unfortunately PHP seems to be referencing $temp to $result not copying it. So no matter what I do, the end result of my WHILE LOOP is always displaying the last fetched row because of the references. Anyone has a solution? ---- Server IP: 66.163.161.117 Probable Submitter: 84.36.231.206 ---- Manual Page -- http://www.php.net/manual/en/function.mysqli-stmt-bind-result.php Edit -- https://master.php.net/note/edit/72015 Del: integrated -- https://master.php.net/note/delete/72015/integrated Del: useless -- https://master.php.net/note/delete/72015/useless Del: bad code -- https://master.php.net/note/delete/72015/bad+code Del: spam -- https://master.php.net/note/delete/72015/spam Del: non-english -- https://master.php.net/note/delete/72015/non-english Del: in docs -- https://master.php.net/note/delete/72015/in+docs Del: other reasons-- https://master.php.net/note/delete/72015 Reject -- https://master.php.net/note/reject/72015 Search -- https://master.php.net/manage/user-notes.php