note 72015 rejected from function.mysqli-stmt-bind-result by nlopess
| From: | nlopess@php.net | Date: | Fri, 29 Dec 2006 14:31:54 +0000 |
| Subject: | note 72015 rejected from function.mysqli-stmt-bind-result by nlopess | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-121007@lists.php.net to get a copy of this message | ||
Note Submitter: Typer85 at gmail dot com
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In response to 'matti at withoutthis dot keller dot com',
Your function works great but there is one thing you should clear up when you say the following:
'# But beware! when using the fetch in a loop, always COPY $result or else you might
# end with all the same values because of the references'.
Can someone explain how exactly to COPY the contents of an array that is referenced?
Myself, I am having a little trouble. In my WHILE LOOP that fetches a result set I have the
following:
<?php
$temp = $result;
?>
This is my understanding of copying an array, unfortunately PHP seems to be referencing $temp to
$result not copying it. So no matter what I do, the end result of my WHILE LOOP is always displaying
the last fetched row because of the references.
Anyone has a solution?