note 76172 added to language.operators.comparison

$a = "iowjoiwef"; $b = 0; print ($a == $b); // is 1 print ("$a" == "$b"); // is 0 Now someone mentions the point that $y = "123"; print (int) $y; // is 123 Why would anyone want "iowjoiwef" to be 0 when casted to int? Why should int take precedence on operator casting when comparing two values, isn't php a string oriented language.. Is it strongly typed? What about operator overloading? Does it offer it? Really? Can we cover up this problem? No? If you want people making more bugs, I suggest you stick with this form of self deception.. This is bad interpreter design.. You might as well compile PHP.. Because it can't be a valid interpreter.. ---- Server IP: 208.69.120.35 Probable Submitter: 69.241.171.211 ---- Manual Page -- http://www.php.net/manual/en/language.operators.comparison.php Edit -- https://master.php.net/note/edit/76172 Del: integrated -- https://master.php.net/note/delete/76172/integrated Del: useless -- https://master.php.net/note/delete/76172/useless Del: bad code -- https://master.php.net/note/delete/76172/bad+code Del: spam -- https://master.php.net/note/delete/76172/spam Del: non-english -- https://master.php.net/note/delete/76172/non-english Del: in docs -- https://master.php.net/note/delete/76172/in+docs Del: other reasons-- https://master.php.net/note/delete/76172 Reject -- https://master.php.net/note/reject/76172 Search -- https://master.php.net/manage/user-notes.php