note 76172 deleted from language.operators.comparison by danbrown

Note Submitter: rofthorax at gmail dot com ---- $a = "iowjoiwef"; $b = 0; print ($a == $b); // is 1 print ("$a" == "$b"); // is 0 Now someone mentions the point that $y = "123"; print (int) $y; // is 123 Why would anyone want "iowjoiwef" to be 0 when casted to int? Why should int take precedence on operator casting when comparing two values, isn't php a string oriented language.. Is it strongly typed? What about operator overloading? Does it offer it? Really? Can we cover up this problem? No? If you want people making more bugs, I suggest you stick with this form of self deception.. This is bad interpreter design.. You might as well compile PHP.. Because it can't be a valid interpreter..