note 111755 added to function.preg-quote

preg_quote() only works on the search string, not the replacement string. But the replacement string isn't always literal, as it can contain backreferences. There's no function to quote the replacement string, but a workaround is to escape all $ and \ signs: $replace = str_replace (array('\\','$'),array('\\\\','\$'),$replace); For example: $text = 'Test: *#5*'; $search = "*#5*"; $replace = "*$5\\1*"; $search = preg_quote($search, "/"); $replace = str_replace (array('\\','$'),array('\\\\','\$'),$replace); $new = preg_replace("/$search/", "$replace", $text); echo "Input: $text\nOutput: $new\n"; Prints: Input: Test: *#5* Output: Test: *$5\1* ---- Server IP: 69.147.83.199 Probable Submitter: 87.194.171.29 ---- Manual Page -- http://php.net/manual/en/function.preg-quote.php Edit -- https://master.php.net/note/edit/111755 Del: integrated -- https://master.php.net/note/delete/111755/integrated Del: useless -- https://master.php.net/note/delete/111755/useless Del: bad code -- https://master.php.net/note/delete/111755/bad+code Del: spam -- https://master.php.net/note/delete/111755/spam Del: non-english -- https://master.php.net/note/delete/111755/non-english Del: in docs -- https://master.php.net/note/delete/111755/in+docs Del: other reasons-- https://master.php.net/note/delete/111755 Reject -- https://master.php.net/note/reject/111755 Search -- https://master.php.net/manage/user-notes.php