note 18079 added to function.preg-replace

If you're using preg_replace with callbacks, you must use the following method to get the matched string parts unmodified to the callback function: function handler($s) { print str_replace('\"', '"', $s); } $s = "\"Don't cause problems, m'kay?\""; print "$s\n"; preg_replace('/^(.*)/e', "handler('\\1')", $s); Point here being, that you must use str_replace in the callback function (to replace \" with "), and the function parameters in singlequotes (to get $-signs unmodified). preg_replace replaces ' with \', \ with \\ and " with \" when parsing the \digit or $digit -sequences in the replacement string. If you omit str_replace, you get extra backslashes, and if you use 'handler("\1")', you get problems with input containing $-signs (plus extra backslashes if you don't do proper str_replace). -- http://www.php.net/manual/en/function.preg-replace.php http://master.php.net/manage/user-notes.php?action=edit+18079 http://master.php.net/manage/user-notes.php?action=delete+18079 http://master.php.net/manage/user-notes.php?action=reject+18079