note 35378 added to language.variables.variable
| From: | Stoker at rack1 dot php dot net | Date: | Fri, 29 Aug 2003 04:18:29 +0000 |
| Subject: | note 35378 added to language.variables.variable | ||
| Groups: | php.notes | ||
| Request: | Send a blank email to php-notes+get-55274@lists.php.net to get a copy of this message | ||
Using variable variables with arrays, I've been searching quite a bit for it and have not found
any solutions, and the comments here indicate the same as what i found, that
$myarray = array ('Sierra Nevada','Sam Adams');
$arraypath = 'myarray[0]';
echo ${$arraypath};
does not work (at least not in PHP 4.3.2).
A "dirty" workaround is to use eval, but be careful and do not use submitted data in the
eval statement directly (Security)..
Instead of the echo above you could do something like
eval ('$myval = $'.$arraypath.';');
echo $myval;
(Could also do echo in the eval, depending on what you need the value for)
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Manual Page -- http://www.php.net/manual/en/language.variables.variable.php
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